Qus : 8 NIMCET PYQ 1 The greatest number which on dividing
1657 and 2037 leaves remainders 6 and 5
respectively is
1 127 2 235 3 123 4 305 Go to Discussion NIMCET Previous Year PYQ NIMCET NIMCET 2022 PYQ Solution The first number = (1657 - 6) = 1651
Second number = (2037 - 5) = 2032
Taking the HCF of two numbers 1651, 2032 we get 127.
So, if we divide 1657 and 2037 by 127 we will get remainders 6 and 5 respectively.
Qus : 9 NIMCET PYQ 4 Suppose the largest n bit number requires ‘d’ digits in decimal representation. Which of the following relations between ‘n’ and ‘d’ is approximately correct
1 $$d=2^n$$ 2 $$n=2^d$$ 3 $$d{\lt}n\log _{10}2$$ 4 $$d{{\gt}}n\log _{10}2$$ Go to Discussion NIMCET Previous Year PYQ NIMCET NIMCET 2022 PYQ Solution n bits binary number required d -decimal digits.
So, ${10}^d{\gt}{2}^n$
Take on both side
$\log _{10}({10}^d)\gt{\log _{10}({2}^n)}^{}$
$d{\gt}n\log _{10}(2)$
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